Solve 23/5+41/5div21/3

$$2 \frac { 3 } { 5 } + 4 \frac { 1 } { 5 } \div 2 \frac { 1 } { 3 }$$

Evaluate

$$\frac{22}{5}=4.4$$

Solution Steps

Multiply 2 and 5 to get 10.

$$\frac{10+3}{5}+\frac{\frac{4\times 5+1}{5}}{\frac{2\times 3+1}{3}}$$

Add 10 and 3 to get 13.

$$\frac{13}{5}+\frac{\frac{4\times 5+1}{5}}{\frac{2\times 3+1}{3}}$$

Divide \frac{4\times 5+1}{5} by \frac{2\times 3+1}{3} by multiplying \frac{4\times 5+1}{5} by the reciprocal of \frac{2\times 3+1}{3}.

$$\frac{13}{5}+\frac{\left(4\times 5+1\right)\times 3}{5\left(2\times 3+1\right)}$$

Multiply 4 and 5 to get 20.

$$\frac{13}{5}+\frac{\left(20+1\right)\times 3}{5\left(2\times 3+1\right)}$$

Add 20 and 1 to get 21.

$$\frac{13}{5}+\frac{21\times 3}{5\left(2\times 3+1\right)}$$

Multiply 21 and 3 to get 63.

$$\frac{13}{5}+\frac{63}{5\left(2\times 3+1\right)}$$

Multiply 2 and 3 to get 6.

$$\frac{13}{5}+\frac{63}{5\left(6+1\right)}$$

Add 6 and 1 to get 7.

$$\frac{13}{5}+\frac{63}{5\times 7}$$

Multiply 5 and 7 to get 35.

$$\frac{13}{5}+\frac{63}{35}$$

Reduce the fraction \frac{63}{35} to lowest terms by extracting and canceling out 7.

$$\frac{13}{5}+\frac{9}{5}$$

Since \frac{13}{5} and \frac{9}{5} have the same denominator, add them by adding their numerators.

$$\frac{13+9}{5}$$

Add 13 and 9 to get 22.

$$\frac{22}{5}$$

Factor

$$\frac{2 \cdot 11}{5} = 4\frac{2}{5} = 4.4$$