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\frac{8+3}{4}\times \frac{2\times 5+4}{5}-\frac{\frac{1\times 2+1}{2}}{\frac{3\times 3+1}{3}}
Multiply 2 and 4 to get 8.
\frac{11}{4}\times \frac{2\times 5+4}{5}-\frac{\frac{1\times 2+1}{2}}{\frac{3\times 3+1}{3}}
Add 8 and 3 to get 11.
\frac{11}{4}\times \frac{10+4}{5}-\frac{\frac{1\times 2+1}{2}}{\frac{3\times 3+1}{3}}
Multiply 2 and 5 to get 10.
\frac{11}{4}\times \frac{14}{5}-\frac{\frac{1\times 2+1}{2}}{\frac{3\times 3+1}{3}}
Add 10 and 4 to get 14.
\frac{11\times 14}{4\times 5}-\frac{\frac{1\times 2+1}{2}}{\frac{3\times 3+1}{3}}
Multiply \frac{11}{4} times \frac{14}{5} by multiplying numerator times numerator and denominator times denominator.
\frac{154}{20}-\frac{\frac{1\times 2+1}{2}}{\frac{3\times 3+1}{3}}
Do the multiplications in the fraction \frac{11\times 14}{4\times 5}.
\frac{77}{10}-\frac{\frac{1\times 2+1}{2}}{\frac{3\times 3+1}{3}}
Reduce the fraction \frac{154}{20} to lowest terms by extracting and canceling out 2.
\frac{77}{10}-\frac{\left(1\times 2+1\right)\times 3}{2\left(3\times 3+1\right)}
Divide \frac{1\times 2+1}{2} by \frac{3\times 3+1}{3} by multiplying \frac{1\times 2+1}{2} by the reciprocal of \frac{3\times 3+1}{3}.
\frac{77}{10}-\frac{\left(2+1\right)\times 3}{2\left(3\times 3+1\right)}
Multiply 1 and 2 to get 2.
\frac{77}{10}-\frac{3\times 3}{2\left(3\times 3+1\right)}
Add 2 and 1 to get 3.
\frac{77}{10}-\frac{9}{2\left(3\times 3+1\right)}
Multiply 3 and 3 to get 9.
\frac{77}{10}-\frac{9}{2\left(9+1\right)}
Multiply 3 and 3 to get 9.
\frac{77}{10}-\frac{9}{2\times 10}
Add 9 and 1 to get 10.
\frac{77}{10}-\frac{9}{20}
Multiply 2 and 10 to get 20.
\frac{154}{20}-\frac{9}{20}
Least common multiple of 10 and 20 is 20. Convert \frac{77}{10} and \frac{9}{20} to fractions with denominator 20.
\frac{154-9}{20}
Since \frac{154}{20} and \frac{9}{20} have the same denominator, subtract them by subtracting their numerators.
\frac{145}{20}
Subtract 9 from 154 to get 145.
\frac{29}{4}
Reduce the fraction \frac{145}{20} to lowest terms by extracting and canceling out 5.