Solve 222/25div113/35

$$2 \frac { 22 } { 25 } \div 1 \frac { 13 } { 35 }$$

Evaluate

$$\frac{21}{10}=2.1$$

Solution Steps

Divide \frac{2\times 25+22}{25} by \frac{1\times 35+13}{35} by multiplying \frac{2\times 25+22}{25} by the reciprocal of \frac{1\times 35+13}{35}.

$$\frac{\left(2\times 25+22\right)\times 35}{25\left(1\times 35+13\right)}$$

Cancel out 5 in both numerator and denominator.

$$\frac{7\left(22+2\times 25\right)}{5\left(13+35\right)}$$

Multiply 2 and 25 to get 50.

$$\frac{7\left(22+50\right)}{5\left(13+35\right)}$$

Add 22 and 50 to get 72.

$$\frac{7\times 72}{5\left(13+35\right)}$$

Multiply 7 and 72 to get 504.

$$\frac{504}{5\left(13+35\right)}$$

Add 13 and 35 to get 48.

$$\frac{504}{5\times 48}$$

Multiply 5 and 48 to get 240.

$$\frac{504}{240}$$

Reduce the fraction \frac{504}{240} to lowest terms by extracting and canceling out 24.

$$\frac{21}{10}$$

Factor

$$\frac{3 \cdot 7}{2 \cdot 5} = 2\frac{1}{10} = 2.1$$