Solve 21/8+12/10

$$2 \frac { 1 } { 8 } + 1 \frac { 2 } { 10 }$$

Evaluate

$$\frac{133}{40}=3.325$$

Solution Steps

Multiply 2 and 8 to get 16.

$$\frac{16+1}{8}+\frac{1\times 10+2}{10}$$

Add 16 and 1 to get 17.

$$\frac{17}{8}+\frac{1\times 10+2}{10}$$

Multiply 1 and 10 to get 10.

$$\frac{17}{8}+\frac{10+2}{10}$$

Add 10 and 2 to get 12.

$$\frac{17}{8}+\frac{12}{10}$$

Reduce the fraction \frac{12}{10} to lowest terms by extracting and canceling out 2.

$$\frac{17}{8}+\frac{6}{5}$$

Least common multiple of 8 and 5 is 40. Convert \frac{17}{8} and \frac{6}{5} to fractions with denominator 40.

$$\frac{85}{40}+\frac{48}{40}$$

Since \frac{85}{40} and \frac{48}{40} have the same denominator, add them by adding their numerators.

$$\frac{85+48}{40}$$

Add 85 and 48 to get 133.

$$\frac{133}{40}$$

Factor

$$\frac{7 \cdot 19}{2 ^ {3} \cdot 5} = 3\frac{13}{40} = 3.325$$