Solve 21/4+11/3

$$2 \frac { 1 } { 4 } + 1 \frac { 1 } { 3 }$$

Evaluate

$$\frac{43}{12}\approx 3.583333333$$

Solution Steps

Multiply 2 and 4 to get 8.

$$\frac{8+1}{4}+\frac{1\times 3+1}{3}$$

Add 8 and 1 to get 9.

$$\frac{9}{4}+\frac{1\times 3+1}{3}$$

Multiply 1 and 3 to get 3.

$$\frac{9}{4}+\frac{3+1}{3}$$

Add 3 and 1 to get 4.

$$\frac{9}{4}+\frac{4}{3}$$

Least common multiple of 4 and 3 is 12. Convert \frac{9}{4} and \frac{4}{3} to fractions with denominator 12.

$$\frac{27}{12}+\frac{16}{12}$$

Since \frac{27}{12} and \frac{16}{12} have the same denominator, add them by adding their numerators.

$$\frac{27+16}{12}$$

Add 27 and 16 to get 43.

$$\frac{43}{12}$$

Factor

$$\frac{43}{2 ^ {2} \cdot 3} = 3\frac{7}{12} = 3.5833333333333335$$