Solve 1x+2y=30y*35z

$$1x+2y = 30y \times 35z$$

Solve for x

$$x=2y\left(525z-1\right)$$

Solution Steps

Multiply 30 and 35 to get 1050.

$$1x+2y=1050yz$$

Subtract 2y from both sides.

$$1x=1050yz-2y$$

Reorder the terms.

$$x=1050yz-2y$$

Solve for y

$$\left\{\begin{matrix}y=-\frac{x}{2\left(1-525z\right)}\text{, }&z\neq \frac{1}{525}\\y\in \mathrm{R}\text{, }&x=0\text{ and }z=\frac{1}{525}\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply 30 and 35 to get 1050.

$$1x+2y=1050yz$$

Subtract 1050yz from both sides.

$$1x+2y-1050yz=0$$

Subtract 1x from both sides. Anything subtracted from zero gives its negation.

$$2y-1050yz=-x$$

Combine all terms containing y.

$$\left(2-1050z\right)y=-x$$

Divide both sides by 2-1050z.

$$\frac{\left(2-1050z\right)y}{2-1050z}=-\frac{x}{2-1050z}$$

Dividing by 2-1050z undoes the multiplication by 2-1050z.

$$y=-\frac{x}{2-1050z}$$

Divide -x by 2-1050z.

$$y=-\frac{x}{2\left(1-525z\right)}$$