Solve 19973/5-19961/6

$$1997 \frac{ 3 }{ 5 } -1996 \frac{ 1 }{ 6 }$$

Evaluate

$$\frac{43}{30}\approx 1.433333333$$

Solution Steps

Multiply 1997 and 5 to get 9985.

$$\frac{9985+3}{5}-\frac{1996\times 6+1}{6}$$

Add 9985 and 3 to get 9988.

$$\frac{9988}{5}-\frac{1996\times 6+1}{6}$$

Multiply 1996 and 6 to get 11976.

$$\frac{9988}{5}-\frac{11976+1}{6}$$

Add 11976 and 1 to get 11977.

$$\frac{9988}{5}-\frac{11977}{6}$$

Least common multiple of 5 and 6 is 30. Convert \frac{9988}{5} and \frac{11977}{6} to fractions with denominator 30.

$$\frac{59928}{30}-\frac{59885}{30}$$

Since \frac{59928}{30} and \frac{59885}{30} have the same denominator, subtract them by subtracting their numerators.

$$\frac{59928-59885}{30}$$

Subtract 59885 from 59928 to get 43.

$$\frac{43}{30}$$

Factor

$$\frac{43}{2 \cdot 3 \cdot 5} = 1\frac{13}{30} = 1.4333333333333333$$