Solve 196+28x+x^2=2x-20+x^2-10x

$$196 + 28 x + x ^ { 2 } = 2 x - 20 + x ^ { 2 } - 10 x$$

Solve for x

$$x=-6$$

Steps for Solving Linear Equation

Combine 2x and -10x to get -8x.

$$196+28x+x^{2}=-8x-20+x^{2}$$

Add 8x to both sides.

$$196+28x+x^{2}+8x=-20+x^{2}$$

Combine 28x and 8x to get 36x.

$$196+36x+x^{2}=-20+x^{2}$$

Subtract x^{2} from both sides.

$$196+36x+x^{2}-x^{2}=-20$$

Combine x^{2} and -x^{2} to get 0.

$$196+36x=-20$$

Subtract 196 from both sides.

$$36x=-20-196$$

Subtract 196 from -20 to get -216.

$$36x=-216$$

Divide both sides by 36.

$$x=\frac{-216}{36}$$

Divide -216 by 36 to get -6.

$$x=-6$$