Solve 1922.28=1917*(1+x)

$$1922.28=1917 \times (1+x)$$

Solve for x

$$x=\frac{44}{15975}\approx 0.002754304$$

Steps for Solving Linear Equation

Divide both sides by 1917.

$$\frac{1922.28}{1917}=1+x$$

Expand \frac{1922.28}{1917} by multiplying both numerator and the denominator by 100.

$$\frac{192228}{191700}=1+x$$

Reduce the fraction \frac{192228}{191700} to lowest terms by extracting and canceling out 12.

$$\frac{16019}{15975}=1+x$$

Swap sides so that all variable terms are on the left hand side.

$$1+x=\frac{16019}{15975}$$

Subtract 1 from both sides.

$$x=\frac{16019}{15975}-1$$

Convert 1 to fraction \frac{15975}{15975}.

$$x=\frac{16019}{15975}-\frac{15975}{15975}$$

Since \frac{16019}{15975} and \frac{15975}{15975} have the same denominator, subtract them by subtracting their numerators.

$$x=\frac{16019-15975}{15975}$$

Subtract 15975 from 16019 to get 44.

$$x=\frac{44}{15975}$$