Solve 192-40*024*08=2x^2

$$192 - 40 \times 024 \times 08 = 2 x ^ { 2 }$$

Solve for x

$$x=4\sqrt{6}\approx 9.797958971$$

$$x=-4\sqrt{6}\approx -9.797958971$$

Steps by Finding Square Root

Multiply 40 and 0 to get 0.

$$192-0\times 24\times 0\times 8=2x^{2}$$

Multiply 0 and 24 to get 0.

$$192-0\times 0\times 8=2x^{2}$$

Multiply 0 and 0 to get 0.

$$192-0\times 8=2x^{2}$$

Multiply 0 and 8 to get 0.

$$192-0=2x^{2}$$

Subtract 0 from 192 to get 192.

$$192=2x^{2}$$

Swap sides so that all variable terms are on the left hand side.

$$2x^{2}=192$$

Divide both sides by 2.

$$x^{2}=\frac{192}{2}$$

Divide 192 by 2 to get 96.

$$x^{2}=96$$

Take the square root of both sides of the equation.

$$x=4\sqrt{6} x=-4\sqrt{6}$$

Steps Using the Quadratic Formula

Multiply 40 and 0 to get 0.

$$192-0\times 24\times 0\times 8=2x^{2}$$

Multiply 0 and 24 to get 0.

$$192-0\times 0\times 8=2x^{2}$$

Multiply 0 and 0 to get 0.

$$192-0\times 8=2x^{2}$$

Multiply 0 and 8 to get 0.

$$192-0=2x^{2}$$

Subtract 0 from 192 to get 192.

$$192=2x^{2}$$

Swap sides so that all variable terms are on the left hand side.

$$2x^{2}=192$$

Subtract 192 from both sides.

$$2x^{2}-192=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 2 for a, 0 for b, and -192 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 2\left(-192\right)}}{2\times 2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\times 2\left(-192\right)}}{2\times 2}$$

Multiply -4 times 2.

$$x=\frac{0±\sqrt{-8\left(-192\right)}}{2\times 2}$$

Multiply -8 times -192.

$$x=\frac{0±\sqrt{1536}}{2\times 2}$$

Take the square root of 1536.

$$x=\frac{0±16\sqrt{6}}{2\times 2}$$

Multiply 2 times 2.

$$x=\frac{0±16\sqrt{6}}{4}$$

Now solve the equation x=\frac{0±16\sqrt{6}}{4} when ± is plus.

$$x=4\sqrt{6}$$

Now solve the equation x=\frac{0±16\sqrt{6}}{4} when ± is minus.

$$x=-4\sqrt{6}$$

The equation is now solved.

$$x=4\sqrt{6} x=-4\sqrt{6}$$