Solve 19-(56div2^3+6)^2div(23-10^1*1)=

$$19 - ( 56 \div 2 ^ { 3 } + 6 ) ^ { 2 } \div ( 23 - 10 ^ { 1 } \cdot 1 ) =$$

Evaluate

$$6$$

Solution Steps

Calculate 2 to the power of 3 and get 8.

$$19-\frac{\left(\frac{56}{8}+6\right)^{2}}{23-10^{1}\times 1}$$

Divide 56 by 8 to get 7.

$$19-\frac{\left(7+6\right)^{2}}{23-10^{1}\times 1}$$

Add 7 and 6 to get 13.

$$19-\frac{13^{2}}{23-10^{1}\times 1}$$

Calculate 13 to the power of 2 and get 169.

$$19-\frac{169}{23-10^{1}\times 1}$$

Calculate 10 to the power of 1 and get 10.

$$19-\frac{169}{23-10\times 1}$$

Multiply 10 and 1 to get 10.

$$19-\frac{169}{23-10}$$

Subtract 10 from 23 to get 13.

$$19-\frac{169}{13}$$

Divide 169 by 13 to get 13.

$$19-13$$

Subtract 13 from 19 to get 6.

$$6$$

Factor

$$2\times 3$$