Solve 19leq03x+05x+02(60-x-y)leq20

$$19 \leq 03 x + 05 x + 02 ( 60 - x - y ) \leq 20$$

Evaluate

Solution Steps

Multiply 0 and 3 to get 0. Multiply 0 and 5 to get 0. Multiply 0 and 2 to get 0.

$$19\leq 0x+0x+0\left(60-x-y\right)\text{ and }0\times 3x+0\times 5x+0\times 2\left(60-x-y\right)\leq 20$$

Anything times zero gives zero.

$$19\leq 0+0x+0\left(60-x-y\right)\text{ and }0\times 3x+0\times 5x+0\times 2\left(60-x-y\right)\leq 20$$

Anything times zero gives zero.

$$19\leq 0+0+0\left(60-x-y\right)\text{ and }0\times 3x+0\times 5x+0\times 2\left(60-x-y\right)\leq 20$$

Add 0 and 0 to get 0.

$$19\leq 0\left(60-x-y\right)\text{ and }0\times 3x+0\times 5x+0\times 2\left(60-x-y\right)\leq 20$$

Anything times zero gives zero.

$$19\leq 0\text{ and }0\times 3x+0\times 5x+0\times 2\left(60-x-y\right)\leq 20$$

Compare 19 and 0.

$$\text{false}\text{ and }0\times 3x+0\times 5x+0\times 2\left(60-x-y\right)\leq 20$$

Multiply 0 and 3 to get 0. Multiply 0 and 5 to get 0. Multiply 0 and 2 to get 0.

$$\text{false}\text{ and }0x+0x+0\left(60-x-y\right)\leq 20$$

Anything times zero gives zero.

$$\text{false}\text{ and }0+0x+0\left(60-x-y\right)\leq 20$$

Anything times zero gives zero.

$$\text{false}\text{ and }0+0+0\left(60-x-y\right)\leq 20$$

Add 0 and 0 to get 0.

$$\text{false}\text{ and }0\left(60-x-y\right)\leq 20$$

Anything times zero gives zero.

$$\text{false}\text{ and }0\leq 20$$

Compare 0 and 20.

$$\text{false}\text{ and }\text{true}$$

The conjunction of \text{false} and \text{true} is \text{false}.

$$\text{false}$$