Solve 191/2*1/9+(-1.5)div(-3)^2

$$19 \frac { 1 } { 2 } \times \frac { 1 } { 9 } + ( - 1.5 ) \div ( - 3 ) ^ { 2 }$$

Evaluate

$$2$$

Solution Steps

Multiply 19 and 2 to get 38.

$$\frac{38+1}{2}\times \frac{1}{9}+\frac{-1.5}{\left(-3\right)^{2}}$$

Add 38 and 1 to get 39.

$$\frac{39}{2}\times \frac{1}{9}+\frac{-1.5}{\left(-3\right)^{2}}$$

Multiply \frac{39}{2} times \frac{1}{9} by multiplying numerator times numerator and denominator times denominator.

$$\frac{39\times 1}{2\times 9}+\frac{-1.5}{\left(-3\right)^{2}}$$

Do the multiplications in the fraction \frac{39\times 1}{2\times 9}.

$$\frac{39}{18}+\frac{-1.5}{\left(-3\right)^{2}}$$

Reduce the fraction \frac{39}{18} to lowest terms by extracting and canceling out 3.

$$\frac{13}{6}+\frac{-1.5}{\left(-3\right)^{2}}$$

Calculate -3 to the power of 2 and get 9.

$$\frac{13}{6}+\frac{-1.5}{9}$$

Expand \frac{-1.5}{9} by multiplying both numerator and the denominator by 10.

$$\frac{13}{6}+\frac{-15}{90}$$

Reduce the fraction \frac{-15}{90} to lowest terms by extracting and canceling out 15.

$$\frac{13}{6}-\frac{1}{6}$$

Since \frac{13}{6} and \frac{1}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{13-1}{6}$$

Subtract 1 from 13 to get 12.

$$\frac{12}{6}$$

Divide 12 by 6 to get 2.

$$2$$

Factor

$$2$$