Solve for b
b=\frac{-c-6}{5}
Solve for c
c=-5b-6
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19=25+5b+c
Calculate 5 to the power of 2 and get 25.
25+5b+c=19
Swap sides so that all variable terms are on the left hand side.
5b+c=19-25
Subtract 25 from both sides.
5b+c=-6
Subtract 25 from 19 to get -6.
5b=-6-c
Subtract c from both sides.
5b=-c-6
The equation is in standard form.
\frac{5b}{5}=\frac{-c-6}{5}
Divide both sides by 5.
b=\frac{-c-6}{5}
Dividing by 5 undoes the multiplication by 5.
19=25+5b+c
Calculate 5 to the power of 2 and get 25.
25+5b+c=19
Swap sides so that all variable terms are on the left hand side.
5b+c=19-25
Subtract 25 from both sides.
5b+c=-6
Subtract 25 from 19 to get -6.
c=-6-5b
Subtract 5b from both sides.
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