Solve 19+|238/2-(-11)/50|3=

$$19 + | \frac { \frac { 238 } { 2 } - ( - 11 ) } { 50 } | 3 =$$

Evaluate

$$\frac{134}{5}=26.8$$

Solution Steps

Divide 238 by 2 to get 119.

$$19+|\frac{119-\left(-11\right)}{50}|\times 3$$

The opposite of -11 is 11.

$$19+|\frac{119+11}{50}|\times 3$$

Add 119 and 11 to get 130.

$$19+|\frac{130}{50}|\times 3$$

Reduce the fraction \frac{130}{50} to lowest terms by extracting and canceling out 10.

$$19+|\frac{13}{5}|\times 3$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of \frac{13}{5} is \frac{13}{5}.

$$19+\frac{13}{5}\times 3$$

Express \frac{13}{5}\times 3 as a single fraction.

$$19+\frac{13\times 3}{5}$$

Multiply 13 and 3 to get 39.

$$19+\frac{39}{5}$$

Convert 19 to fraction \frac{95}{5}.

$$\frac{95}{5}+\frac{39}{5}$$

Since \frac{95}{5} and \frac{39}{5} have the same denominator, add them by adding their numerators.

$$\frac{95+39}{5}$$

Add 95 and 39 to get 134.

$$\frac{134}{5}$$

Factor

$$\frac{2 \cdot 67}{5} = 26\frac{4}{5} = 26.8$$