Solve for x
x<30
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1800+50x<2040+42x
Multiply 42 and 1 to get 42.
1800+50x-42x<2040
Subtract 42x from both sides.
1800+8x<2040
Combine 50x and -42x to get 8x.
8x<2040-1800
Subtract 1800 from both sides.
8x<240
Subtract 1800 from 2040 to get 240.
x<\frac{240}{8}
Divide both sides by 8. Since 8 is positive, the inequality direction remains the same.
x<30
Divide 240 by 8 to get 30.
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Limits
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