Solve 180=b-aGamma

$$180 = b - a \Gamma$$

Solve for a

$$\left\{\begin{matrix}a=\frac{b-180}{\Gamma }\text{, }&\Gamma \neq 0\\a\in \mathrm{R}\text{, }&b=180\text{ and }\Gamma =0\end{matrix}\right.$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$b-a\Gamma =180$$

Subtract b from both sides.

$$-a\Gamma =180-b$$

The equation is in standard form.

$$\left(-\Gamma \right)a=180-b$$

Divide both sides by -\Gamma .

$$\frac{\left(-\Gamma \right)a}{-\Gamma }=\frac{180-b}{-\Gamma }$$

Dividing by -\Gamma undoes the multiplication by -\Gamma .

$$a=\frac{180-b}{-\Gamma }$$

Divide 180-b by -\Gamma .

$$a=\frac{b-180}{\Gamma }$$

Solve for b

$$b=a\Gamma +180$$

Solution Steps

Swap sides so that all variable terms are on the left hand side.

$$b-a\Gamma =180$$

Add a\Gamma to both sides.

$$b=180+a\Gamma$$