Solve 180=2^x*3^2*5th

$$180 = 2 ^ { x } \times 3 ^ { 2 } \times 5 th$$

Solve for h

$$h=\frac{4}{t\times 2^{x}}$$

$$t\neq 0$$

Steps for Solving Linear Equation

Calculate 3 to the power of 2 and get 9.

$$180=2^{x}\times 9\times 5th$$

Multiply 9 and 5 to get 45.

$$180=2^{x}\times 45th$$

Swap sides so that all variable terms are on the left hand side.

$$2^{x}\times 45th=180$$

The equation is in standard form.

$$45t\times 2^{x}h=180$$

Divide both sides by 45\times 2^{x}t.

$$\frac{45t\times 2^{x}h}{45t\times 2^{x}}=\frac{180}{45t\times 2^{x}}$$

Dividing by 45\times 2^{x}t undoes the multiplication by 45\times 2^{x}t.

$$h=\frac{180}{45t\times 2^{x}}$$

Divide 180 by 45\times 2^{x}t.

$$h=\frac{2^{2-x}}{t}$$

Solve for t

$$t=\frac{4}{h\times 2^{x}}$$

$$h\neq 0$$

Steps for Solving Linear Equation

Calculate 3 to the power of 2 and get 9.

$$180=2^{x}\times 9\times 5th$$

Multiply 9 and 5 to get 45.

$$180=2^{x}\times 45th$$

Swap sides so that all variable terms are on the left hand side.

$$2^{x}\times 45th=180$$

The equation is in standard form.

$$45h\times 2^{x}t=180$$

Divide both sides by 45\times 2^{x}h.

$$\frac{45h\times 2^{x}t}{45h\times 2^{x}}=\frac{180}{45h\times 2^{x}}$$

Dividing by 45\times 2^{x}h undoes the multiplication by 45\times 2^{x}h.

$$t=\frac{180}{45h\times 2^{x}}$$

Divide 180 by 45\times 2^{x}h.

$$t=\frac{2^{2-x}}{h}$$