Solve 180=x+3d+θ

$$180 = x+3d+ \theta$$

Solve for d

$$d=-\frac{x}{3}-\frac{\theta }{3}+60$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$x+3d+\theta =180$$

Subtract x from both sides.

$$3d+\theta =180-x$$

Subtract \theta from both sides.

$$3d=180-x-\theta$$

The equation is in standard form.

$$3d=180-\theta -x$$

Divide both sides by 3.

$$\frac{3d}{3}=\frac{180-\theta -x}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$d=\frac{180-\theta -x}{3}$$

Divide 180-x-\theta by 3.

$$d=-\frac{x}{3}-\frac{\theta }{3}+60$$

Solve for x

$$x=180-\theta -3d$$

Solution Steps

Swap sides so that all variable terms are on the left hand side.

$$x+3d+\theta =180$$

Subtract 3d from both sides.

$$x+\theta =180-3d$$

Subtract \theta from both sides.

$$x=180-3d-\theta$$