Solve 18+6/-4-(-4^2

$$18+ \frac{ 6 }{ -4 } -(- { 4 }^{ 2 }$$

Evaluate

$$\frac{65}{2}=32.5$$

Solution Steps

Reduce the fraction \frac{6}{-4} to lowest terms by extracting and canceling out 2.

$$18-\frac{3}{2}-\left(-4^{2}\right)$$

Convert 18 to fraction \frac{36}{2}.

$$\frac{36}{2}-\frac{3}{2}-\left(-4^{2}\right)$$

Since \frac{36}{2} and \frac{3}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{36-3}{2}-\left(-4^{2}\right)$$

Subtract 3 from 36 to get 33.

$$\frac{33}{2}-\left(-4^{2}\right)$$

Calculate 4 to the power of 2 and get 16.

$$\frac{33}{2}-\left(-16\right)$$

The opposite of -16 is 16.

$$\frac{33}{2}+16$$

Convert 16 to fraction \frac{32}{2}.

$$\frac{33}{2}+\frac{32}{2}$$

Since \frac{33}{2} and \frac{32}{2} have the same denominator, add them by adding their numerators.

$$\frac{33+32}{2}$$

Add 33 and 32 to get 65.

$$\frac{65}{2}$$

Factor

$$\frac{5 \cdot 13}{2} = 32\frac{1}{2} = 32.5$$