Solve 18y^2-9x-5=0

$$18 y ^ { 2 } - 9 x - 5 = 0$$

Solve for x

$$x=2y^{2}-\frac{5}{9}$$

Steps for Solving Linear Equation

Subtract 18y^{2} from both sides. Anything subtracted from zero gives its negation.

$$-9x-5=-18y^{2}$$

Add 5 to both sides.

$$-9x=-18y^{2}+5$$

The equation is in standard form.

$$-9x=5-18y^{2}$$

Divide both sides by -9.

$$\frac{-9x}{-9}=\frac{5-18y^{2}}{-9}$$

Dividing by -9 undoes the multiplication by -9.

$$x=\frac{5-18y^{2}}{-9}$$

Divide -18y^{2}+5 by -9.

$$x=2y^{2}-\frac{5}{9}$$

Solve for y (complex solution)

$$y=-\frac{\sqrt{18x+10}}{6}$$

$$y=\frac{\sqrt{18x+10}}{6}$$

Solve for y

$$y=\frac{\sqrt{18x+10}}{6}$$

$$y=-\frac{\sqrt{18x+10}}{6}\text{, }x\geq -\frac{5}{9}$$