Solve 18n+306=an+3

$$18 n + 306 = a n + 3$$

Solve for a

$$a=18+\frac{303}{n}$$

$$n\neq 0$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$an+3=18n+306$$

Subtract 3 from both sides.

$$an=18n+306-3$$

Subtract 3 from 306 to get 303.

$$an=18n+303$$

The equation is in standard form.

$$na=18n+303$$

Divide both sides by n.

$$\frac{na}{n}=\frac{18n+303}{n}$$

Dividing by n undoes the multiplication by n.

$$a=\frac{18n+303}{n}$$

Divide 18n+303 by n.

$$a=18+\frac{303}{n}$$

Solve for n

$$n=-\frac{303}{18-a}$$

$$a\neq 18$$

Steps for Solving Linear Equation

Subtract an from both sides.

$$18n+306-an=3$$

Subtract 306 from both sides.

$$18n-an=3-306$$

Subtract 306 from 3 to get -303.

$$18n-an=-303$$

Combine all terms containing n.

$$\left(18-a\right)n=-303$$

Divide both sides by 18-a.

$$\frac{\left(18-a\right)n}{18-a}=-\frac{303}{18-a}$$

Dividing by 18-a undoes the multiplication by 18-a.

$$n=-\frac{303}{18-a}$$