Solve 18E=40/3-(16/3-4/3y)-2y=

$$18 E = \frac { 40 } { 3 } - ( \frac { 16 } { 3 } - \frac { 4 } { 3 } y ) - 2 y =$$

Solve for E

$$E=-\frac{y}{27}+\frac{4}{9}$$

Steps for Solving Linear Equation

To find the opposite of \frac{16}{3}-\frac{4}{3}y, find the opposite of each term.

$$18E=\frac{40}{3}-\frac{16}{3}+\frac{4}{3}y-2y$$

Subtract \frac{16}{3} from \frac{40}{3} to get 8.

$$18E=8+\frac{4}{3}y-2y$$

Combine \frac{4}{3}y and -2y to get -\frac{2}{3}y.

$$18E=8-\frac{2}{3}y$$

The equation is in standard form.

$$18E=-\frac{2y}{3}+8$$

Divide both sides by 18.

$$\frac{18E}{18}=\frac{-\frac{2y}{3}+8}{18}$$

Dividing by 18 undoes the multiplication by 18.

$$E=\frac{-\frac{2y}{3}+8}{18}$$

Divide 8-\frac{2y}{3} by 18.

$$E=-\frac{y}{27}+\frac{4}{9}$$

Solve for y

$$y=12-27E$$

Steps for Solving Linear Equation

To find the opposite of \frac{16}{3}-\frac{4}{3}y, find the opposite of each term.

$$18E=\frac{40}{3}-\frac{16}{3}+\frac{4}{3}y-2y$$

Subtract \frac{16}{3} from \frac{40}{3} to get 8.

$$18E=8+\frac{4}{3}y-2y$$

Combine \frac{4}{3}y and -2y to get -\frac{2}{3}y.

$$18E=8-\frac{2}{3}y$$

Swap sides so that all variable terms are on the left hand side.

$$8-\frac{2}{3}y=18E$$

Subtract 8 from both sides.

$$-\frac{2}{3}y=18E-8$$

Divide both sides of the equation by -\frac{2}{3}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{-\frac{2}{3}y}{-\frac{2}{3}}=\frac{18E-8}{-\frac{2}{3}}$$

Dividing by -\frac{2}{3} undoes the multiplication by -\frac{2}{3}.

$$y=\frac{18E-8}{-\frac{2}{3}}$$

Divide 18E-8 by -\frac{2}{3} by multiplying 18E-8 by the reciprocal of -\frac{2}{3}.

$$y=12-27E$$