Solve 18-ygeq4(y-3)

$$18 - y \geq 4 ( y - 3 )$$

Solve for y

$$y\leq 6$$

Solution Steps

Use the distributive property to multiply 4 by y-3.

$$18-y\geq 4y-12$$

Subtract 4y from both sides.

$$18-y-4y\geq -12$$

Combine -y and -4y to get -5y.

$$18-5y\geq -12$$

Subtract 18 from both sides.

$$-5y\geq -12-18$$

Subtract 18 from -12 to get -30.

$$-5y\geq -30$$

Divide both sides by -5. Since -5 is negative, the inequality direction is changed.

$$y\leq \frac{-30}{-5}$$

Divide -30 by -5 to get 6.

$$y\leq 6$$