Solve for x
x\leq \frac{9}{2}
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18-3x-x\geq 0
Subtract x from both sides.
18-4x\geq 0
Combine -3x and -x to get -4x.
-4x\geq -18
Subtract 18 from both sides. Anything subtracted from zero gives its negation.
x\leq \frac{-18}{-4}
Divide both sides by -4. Since -4 is negative, the inequality direction is changed.
x\leq \frac{9}{2}
Reduce the fraction \frac{-18}{-4} to lowest terms by extracting and canceling out -2.
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y = 3x + 4
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Matrix
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Simultaneous equation
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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