Solve 18+9-4*(48:4-42:6)+(57:19+5)*2-45*3-1557

$$18 + 9 - 4 \times ( 48 : 4 - 42 : 6 ) + ( 57 : 19 + 5 ) \times 2 - 45 \cdot 3 - 1557$$

Evaluate

$$-1669$$

Solution Steps

Add 18 and 9 to get 27.

$$27-4\left(\frac{48}{4}-\frac{42}{6}\right)+\left(\frac{57}{19}+5\right)\times 2-45\times 3-1557$$

Divide 48 by 4 to get 12.

$$27-4\left(12-\frac{42}{6}\right)+\left(\frac{57}{19}+5\right)\times 2-45\times 3-1557$$

Divide 42 by 6 to get 7.

$$27-4\left(12-7\right)+\left(\frac{57}{19}+5\right)\times 2-45\times 3-1557$$

Subtract 7 from 12 to get 5.

$$27-4\times 5+\left(\frac{57}{19}+5\right)\times 2-45\times 3-1557$$

Multiply 4 and 5 to get 20.

$$27-20+\left(\frac{57}{19}+5\right)\times 2-45\times 3-1557$$

Subtract 20 from 27 to get 7.

$$7+\left(\frac{57}{19}+5\right)\times 2-45\times 3-1557$$

Divide 57 by 19 to get 3.

$$7+\left(3+5\right)\times 2-45\times 3-1557$$

Add 3 and 5 to get 8.

$$7+8\times 2-45\times 3-1557$$

Multiply 8 and 2 to get 16.

$$7+16-45\times 3-1557$$

Add 7 and 16 to get 23.

$$23-45\times 3-1557$$

Multiply 45 and 3 to get 135.

$$23-135-1557$$

Subtract 135 from 23 to get -112.

$$-112-1557$$

Subtract 1557 from -112 to get -1669.

$$-1669$$

Factor

$$-1669$$