Solve 183/4-129/12

$$18 \frac { 3 } { 4 } -12 \frac{ 9 }{ 12 }$$

Evaluate

$$6$$

Solution Steps

Multiply 18 and 4 to get 72.

$$\frac{72+3}{4}-\frac{12\times 12+9}{12}$$

Add 72 and 3 to get 75.

$$\frac{75}{4}-\frac{12\times 12+9}{12}$$

Multiply 12 and 12 to get 144.

$$\frac{75}{4}-\frac{144+9}{12}$$

Add 144 and 9 to get 153.

$$\frac{75}{4}-\frac{153}{12}$$

Reduce the fraction \frac{153}{12} to lowest terms by extracting and canceling out 3.

$$\frac{75}{4}-\frac{51}{4}$$

Since \frac{75}{4} and \frac{51}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{75-51}{4}$$

Subtract 51 from 75 to get 24.

$$\frac{24}{4}$$

Divide 24 by 4 to get 6.

$$6$$

Factor

$$2\times 3$$