Solve for n
n=-\frac{5}{3}+\frac{350}{3\Delta }
\Delta \neq 0
Solve for Δ
\Delta =\frac{350}{3n+5}
n\neq -\frac{5}{3}
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175\times 2=\Delta \left(4+3n+1\right)
Multiply both sides by 2.
350=\Delta \left(4+3n+1\right)
Multiply 175 and 2 to get 350.
350=\Delta \left(5+3n\right)
Add 4 and 1 to get 5.
350=5\Delta +3\Delta n
Use the distributive property to multiply \Delta by 5+3n.
5\Delta +3\Delta n=350
Swap sides so that all variable terms are on the left hand side.
3\Delta n=350-5\Delta
Subtract 5\Delta from both sides.
\frac{3\Delta n}{3\Delta }=\frac{350-5\Delta }{3\Delta }
Divide both sides by 3\Delta .
n=\frac{350-5\Delta }{3\Delta }
Dividing by 3\Delta undoes the multiplication by 3\Delta .
n=-\frac{5}{3}+\frac{350}{3\Delta }
Divide 350-5\Delta by 3\Delta .
175\times 2=\Delta \left(4+3n+1\right)
Multiply both sides by 2.
350=\Delta \left(4+3n+1\right)
Multiply 175 and 2 to get 350.
350=\Delta \left(5+3n\right)
Add 4 and 1 to get 5.
350=5\Delta +3\Delta n
Use the distributive property to multiply \Delta by 5+3n.
5\Delta +3\Delta n=350
Swap sides so that all variable terms are on the left hand side.
\left(5+3n\right)\Delta =350
Combine all terms containing \Delta .
\left(3n+5\right)\Delta =350
The equation is in standard form.
\frac{\left(3n+5\right)\Delta }{3n+5}=\frac{350}{3n+5}
Divide both sides by 5+3n.
\Delta =\frac{350}{3n+5}
Dividing by 5+3n undoes the multiplication by 5+3n.
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