Solve 17f(x)=1/x^2-4=

$$17 f ( x ) = \frac { 1 } { x ^ { 2 } - 4 } =$$

Solve for f

$$f=\frac{1}{17x\left(x^{2}-4\right)}$$

$$x\neq 0\text{ and }|x|\neq 2$$

Steps for Solving Linear Equation

Multiply both sides of the equation by \left(x-2\right)\left(x+2\right).

$$17fx\left(x-2\right)\left(x+2\right)=1$$

Use the distributive property to multiply 17fx by x-2.

$$\left(17fx^{2}-34fx\right)\left(x+2\right)=1$$

Use the distributive property to multiply 17fx^{2}-34fx by x+2 and combine like terms.

$$17fx^{3}-68fx=1$$

Combine all terms containing f.

$$\left(17x^{3}-68x\right)f=1$$

Divide both sides by 17x^{3}-68x.

$$\frac{\left(17x^{3}-68x\right)f}{17x^{3}-68x}=\frac{1}{17x^{3}-68x}$$

Dividing by 17x^{3}-68x undoes the multiplication by 17x^{3}-68x.

$$f=\frac{1}{17x^{3}-68x}$$

Divide 1 by 17x^{3}-68x.

$$f=\frac{1}{17x\left(x^{2}-4\right)}$$