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17-x^{2}=25-\left(16-8x+x^{2}\right)
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(4-x\right)^{2}.
17-x^{2}=25-16+8x-x^{2}
To find the opposite of 16-8x+x^{2}, find the opposite of each term.
17-x^{2}=9+8x-x^{2}
Subtract 16 from 25 to get 9.
17-x^{2}-8x=9-x^{2}
Subtract 8x from both sides.
17-x^{2}-8x+x^{2}=9
Add x^{2} to both sides.
17-8x=9
Combine -x^{2} and x^{2} to get 0.
-8x=9-17
Subtract 17 from both sides.
-8x=-8
Subtract 17 from 9 to get -8.
x=\frac{-8}{-8}
Divide both sides by -8.
x=1
Divide -8 by -8 to get 1.