Solve 17left(1-1/6right)=141/6=77

$$17 \left( 1- \frac{ 1 }{ 6 } \right) = 14 \frac{ 1 }{ 6 } =77$$

Verify

Solution Steps

Convert 1 to fraction \frac{6}{6}.

$$17\left(\frac{6}{6}-\frac{1}{6}\right)=\frac{14\times 6+1}{6}\text{ and }\frac{14\times 6+1}{6}=77$$

Since \frac{6}{6} and \frac{1}{6} have the same denominator, subtract them by subtracting their numerators.

$$17\times \frac{6-1}{6}=\frac{14\times 6+1}{6}\text{ and }\frac{14\times 6+1}{6}=77$$

Subtract 1 from 6 to get 5.

$$17\times \frac{5}{6}=\frac{14\times 6+1}{6}\text{ and }\frac{14\times 6+1}{6}=77$$

Express 17\times \frac{5}{6} as a single fraction.

$$\frac{17\times 5}{6}=\frac{14\times 6+1}{6}\text{ and }\frac{14\times 6+1}{6}=77$$

Multiply 17 and 5 to get 85.

$$\frac{85}{6}=\frac{14\times 6+1}{6}\text{ and }\frac{14\times 6+1}{6}=77$$

Multiply 14 and 6 to get 84.

$$\frac{85}{6}=\frac{84+1}{6}\text{ and }\frac{14\times 6+1}{6}=77$$

Add 84 and 1 to get 85.

$$\frac{85}{6}=\frac{85}{6}\text{ and }\frac{14\times 6+1}{6}=77$$

Compare \frac{85}{6} and \frac{85}{6}.

$$\text{true}\text{ and }\frac{14\times 6+1}{6}=77$$

Multiply 14 and 6 to get 84.

$$\text{true}\text{ and }\frac{84+1}{6}=77$$

Add 84 and 1 to get 85.

$$\text{true}\text{ and }\frac{85}{6}=77$$

Convert 77 to fraction \frac{462}{6}.

$$\text{true}\text{ and }\frac{85}{6}=\frac{462}{6}$$

Compare \frac{85}{6} and \frac{462}{6}.

$$\text{true}\text{ and }\text{false}$$

The conjunction of \text{true} and \text{false} is \text{false}.

$$\text{false}$$