Solve 171/3+13+11/2

$$17 \frac { 1 } { 3 } + 13 + 1 \frac { 1 } { 2 }$$

Evaluate

$$\frac{191}{6}\approx 31.833333333$$

Solution Steps

Multiply 17 and 3 to get 51.

$$\frac{51+1}{3}+13+\frac{1\times 2+1}{2}$$

Add 51 and 1 to get 52.

$$\frac{52}{3}+13+\frac{1\times 2+1}{2}$$

Convert 13 to fraction \frac{39}{3}.

$$\frac{52}{3}+\frac{39}{3}+\frac{1\times 2+1}{2}$$

Since \frac{52}{3} and \frac{39}{3} have the same denominator, add them by adding their numerators.

$$\frac{52+39}{3}+\frac{1\times 2+1}{2}$$

Add 52 and 39 to get 91.

$$\frac{91}{3}+\frac{1\times 2+1}{2}$$

Multiply 1 and 2 to get 2.

$$\frac{91}{3}+\frac{2+1}{2}$$

Add 2 and 1 to get 3.

$$\frac{91}{3}+\frac{3}{2}$$

Least common multiple of 3 and 2 is 6. Convert \frac{91}{3} and \frac{3}{2} to fractions with denominator 6.

$$\frac{182}{6}+\frac{9}{6}$$

Since \frac{182}{6} and \frac{9}{6} have the same denominator, add them by adding their numerators.

$$\frac{182+9}{6}$$

Add 182 and 9 to get 191.

$$\frac{191}{6}$$

Factor

$$\frac{191}{2 \cdot 3} = 31\frac{5}{6} = 31.833333333333332$$