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17^{3n-3.9}=1
Use the rules of exponents and logarithms to solve the equation.
\log(17^{3n-3.9})=\log(1)
Take the logarithm of both sides of the equation.
\left(3n-3.9\right)\log(17)=\log(1)
The logarithm of a number raised to a power is the power times the logarithm of the number.
3n-3.9=\frac{\log(1)}{\log(17)}
Divide both sides by \log(17).
3n-3.9=\log_{17}\left(1\right)
By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).
3n=-\left(-3.9\right)
Add 3.9 to both sides of the equation.
n=\frac{3.9}{3}
Divide both sides by 3.