Solve 17^2-(sqrt[3]{13.824})*(sqrt{64})+9^3

$$17 ^ { 2 } - ( \sqrt[ 3 ] { 13.824 } ) \cdot ( \sqrt { 64 } ) + 9 ^ { 3 }$$

Evaluate

$$998.8$$

Solution Steps

Calculate 17 to the power of 2 and get 289.

$$289-\sqrt[3]{13.824}\sqrt{64}+9^{3}$$

Calculate \sqrt[3]{13.824} and get \frac{12}{5}.

$$289-\frac{12}{5}\sqrt{64}+9^{3}$$

Calculate the square root of 64 and get 8.

$$289-\frac{12}{5}\times 8+9^{3}$$

Multiply \frac{12}{5} and 8 to get \frac{96}{5}.

$$289-\frac{96}{5}+9^{3}$$

Subtract \frac{96}{5} from 289 to get \frac{1349}{5}.

$$\frac{1349}{5}+9^{3}$$

Calculate 9 to the power of 3 and get 729.

$$\frac{1349}{5}+729$$

Add \frac{1349}{5} and 729 to get \frac{4994}{5}.

$$\frac{4994}{5}$$

Factor

$$\frac{2 \cdot 11 \cdot 227}{5} = 998\frac{4}{5} = 998.8$$