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289=8^{2}+x^{2}
Calculate 17 to the power of 2 and get 289.
289=64+x^{2}
Calculate 8 to the power of 2 and get 64.
64+x^{2}=289
Swap sides so that all variable terms are on the left hand side.
64+x^{2}-289=0
Subtract 289 from both sides.
-225+x^{2}=0
Subtract 289 from 64 to get -225.
\left(x-15\right)\left(x+15\right)=0
Consider -225+x^{2}. Rewrite -225+x^{2} as x^{2}-15^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
x=15 x=-15
To find equation solutions, solve x-15=0 and x+15=0.
289=8^{2}+x^{2}
Calculate 17 to the power of 2 and get 289.
289=64+x^{2}
Calculate 8 to the power of 2 and get 64.
64+x^{2}=289
Swap sides so that all variable terms are on the left hand side.
x^{2}=289-64
Subtract 64 from both sides.
x^{2}=225
Subtract 64 from 289 to get 225.
x=15 x=-15
Take the square root of both sides of the equation.
289=8^{2}+x^{2}
Calculate 17 to the power of 2 and get 289.
289=64+x^{2}
Calculate 8 to the power of 2 and get 64.
64+x^{2}=289
Swap sides so that all variable terms are on the left hand side.
64+x^{2}-289=0
Subtract 289 from both sides.
-225+x^{2}=0
Subtract 289 from 64 to get -225.
x^{2}-225=0
Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.
x=\frac{0±\sqrt{0^{2}-4\left(-225\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -225 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\left(-225\right)}}{2}
Square 0.
x=\frac{0±\sqrt{900}}{2}
Multiply -4 times -225.
x=\frac{0±30}{2}
Take the square root of 900.
x=15
Now solve the equation x=\frac{0±30}{2} when ± is plus. Divide 30 by 2.
x=-15
Now solve the equation x=\frac{0±30}{2} when ± is minus. Divide -30 by 2.
x=15 x=-15
The equation is now solved.