Solve 17:(1/3)^-2-(-1)^2018-(-2)^3+2019^0

$$17 : ( \frac { 1 } { 3 } ) ^ { - 2 } - ( - 1 ) ^ { 2018 } - ( - 2 ) ^ { 3 } + 2019 ^ { 0 }$$

Evaluate

$$\frac{89}{9}\approx 9.888888889$$

Solution Steps

Calculate \frac{1}{3} to the power of -2 and get 9.

$$\frac{17}{9}-\left(-1\right)^{2018}-\left(-2\right)^{3}+2019^{0}$$

Calculate -1 to the power of 2018 and get 1.

$$\frac{17}{9}-1-\left(-2\right)^{3}+2019^{0}$$

Subtract 1 from \frac{17}{9} to get \frac{8}{9}.

$$\frac{8}{9}-\left(-2\right)^{3}+2019^{0}$$

Calculate -2 to the power of 3 and get -8.

$$\frac{8}{9}-\left(-8\right)+2019^{0}$$

The opposite of -8 is 8.

$$\frac{8}{9}+8+2019^{0}$$

Add \frac{8}{9} and 8 to get \frac{80}{9}.

$$\frac{80}{9}+2019^{0}$$

Calculate 2019 to the power of 0 and get 1.

$$\frac{80}{9}+1$$

Add \frac{80}{9} and 1 to get \frac{89}{9}.

$$\frac{89}{9}$$

Factor

$$\frac{89}{3 ^ {2}} = 9\frac{8}{9} = 9.88888888888889$$