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\pi r^{2}=1615
Swap sides so that all variable terms are on the left hand side.
\frac{\pi r^{2}}{\pi }=\frac{1615}{\pi }
Divide both sides by \pi .
r^{2}=\frac{1615}{\pi }
Dividing by \pi undoes the multiplication by \pi .
r=\frac{1615}{\sqrt{1615\pi }} r=-\frac{1615}{\sqrt{1615\pi }}
Take the square root of both sides of the equation.
\pi r^{2}=1615
Swap sides so that all variable terms are on the left hand side.
\pi r^{2}-1615=0
Subtract 1615 from both sides.
r=\frac{0±\sqrt{0^{2}-4\pi \left(-1615\right)}}{2\pi }
This equation is in standard form: ax^{2}+bx+c=0. Substitute \pi for a, 0 for b, and -1615 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
r=\frac{0±\sqrt{-4\pi \left(-1615\right)}}{2\pi }
Square 0.
r=\frac{0±\sqrt{\left(-4\pi \right)\left(-1615\right)}}{2\pi }
Multiply -4 times \pi .
r=\frac{0±\sqrt{6460\pi }}{2\pi }
Multiply -4\pi times -1615.
r=\frac{0±2\sqrt{1615\pi }}{2\pi }
Take the square root of 6460\pi .
r=\frac{1615}{\sqrt{1615\pi }}
Now solve the equation r=\frac{0±2\sqrt{1615\pi }}{2\pi } when ± is plus.
r=-\frac{1615}{\sqrt{1615\pi }}
Now solve the equation r=\frac{0±2\sqrt{1615\pi }}{2\pi } when ± is minus.
r=\frac{1615}{\sqrt{1615\pi }} r=-\frac{1615}{\sqrt{1615\pi }}
The equation is now solved.