Solve 160-(2x+x)+(2x*1)-(x*5)=300

$$160 - ( 2 x + x ) + ( 2 x \times 1 ) - ( x \times 5 ) = 300$$

Solve for x

$$x = -\frac{70}{3} = -23\frac{1}{3} \approx -23.333333333$$

Steps for Solving Linear Equation

Combine 2x and x to get 3x.

$$160-3x+2x\times 1-x\times 5=300$$

Multiply 2 and 1 to get 2.

$$160-3x+2x-x\times 5=300$$

Combine -3x and 2x to get -x.

$$160-x-x\times 5=300$$

Combine -x and -x\times 5 to get -6x.

$$160-6x=300$$

Subtract 160 from both sides.

$$-6x=300-160$$

Subtract 160 from 300 to get 140.

$$-6x=140$$

Divide both sides by -6.

$$x=\frac{140}{-6}$$

Reduce the fraction \frac{140}{-6} to lowest terms by extracting and canceling out 2.

$$x=-\frac{70}{3}$$