Solve 16,09-(-8,4)*(-7/12)-(-3,7)^2

$$16,09 - ( - 8,4 ) \cdot ( - \frac { 7 } { 12 } ) - ( - 3,7 ) ^ { 2 }$$

Evaluate

$$-2,5$$

Solution Steps

Convert decimal number -8,4 to fraction -\frac{84}{10}. Reduce the fraction -\frac{84}{10} to lowest terms by extracting and canceling out 2.

$$16,09-\left(-\frac{42}{5}\left(-\frac{7}{12}\right)\right)-\left(-3,7\right)^{2}$$

Multiply -\frac{42}{5} times -\frac{7}{12} by multiplying numerator times numerator and denominator times denominator.

$$16,09-\frac{-42\left(-7\right)}{5\times 12}-\left(-3,7\right)^{2}$$

Do the multiplications in the fraction \frac{-42\left(-7\right)}{5\times 12}.

$$16,09-\frac{294}{60}-\left(-3,7\right)^{2}$$

Reduce the fraction \frac{294}{60} to lowest terms by extracting and canceling out 6.

$$16,09-\frac{49}{10}-\left(-3,7\right)^{2}$$

Convert decimal number 16,09 to fraction \frac{1609}{100}.

$$\frac{1609}{100}-\frac{49}{10}-\left(-3,7\right)^{2}$$

Least common multiple of 100 and 10 is 100. Convert \frac{1609}{100} and \frac{49}{10} to fractions with denominator 100.

$$\frac{1609}{100}-\frac{490}{100}-\left(-3,7\right)^{2}$$

Since \frac{1609}{100} and \frac{490}{100} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1609-490}{100}-\left(-3,7\right)^{2}$$

Subtract 490 from 1609 to get 1119.

$$\frac{1119}{100}-\left(-3,7\right)^{2}$$

Calculate -3,7 to the power of 2 and get 13,69.

$$\frac{1119}{100}-13,69$$

Convert decimal number 13,69 to fraction \frac{1369}{100}.

$$\frac{1119}{100}-\frac{1369}{100}$$

Since \frac{1119}{100} and \frac{1369}{100} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1119-1369}{100}$$

Subtract 1369 from 1119 to get -250.

$$\frac{-250}{100}$$

Reduce the fraction \frac{-250}{100} to lowest terms by extracting and canceling out 50.

$$-\frac{5}{2}$$

Factor

$$-2,5$$