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\left(4x^{4}-5y^{3}\right)\left(4x^{4}+5y^{3}\right)
Rewrite 16x^{8}-25y^{6} as \left(4x^{4}\right)^{2}-\left(5y^{3}\right)^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).