Factor
\frac{\left(4x-1\right)\left(4x+1\right)\left(16x^{2}+1\right)}{16}
Evaluate
16x^{4}-\frac{1}{16}
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\frac{256x^{4}-1}{16}
Factor out \frac{1}{16}.
\left(16x^{2}-1\right)\left(16x^{2}+1\right)
Consider 256x^{4}-1. Rewrite 256x^{4}-1 as \left(16x^{2}\right)^{2}-1^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
\left(4x-1\right)\left(4x+1\right)
Consider 16x^{2}-1. Rewrite 16x^{2}-1 as \left(4x\right)^{2}-1^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
\frac{\left(4x-1\right)\left(4x+1\right)\left(16x^{2}+1\right)}{16}
Rewrite the complete factored expression. Polynomial 16x^{2}+1 is not factored since it does not have any rational roots.
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