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2\left(8x^{3}-125\right)
Factor out 2.
\left(2x-5\right)\left(4x^{2}+10x+25\right)
Consider 8x^{3}-125. Rewrite 8x^{3}-125 as \left(2x\right)^{3}-5^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right).
2\left(2x-5\right)\left(4x^{2}+10x+25\right)
Rewrite the complete factored expression. Polynomial 4x^{2}+10x+25 is not factored since it does not have any rational roots.