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16x^{2}=8
Add 8 to both sides. Anything plus zero gives itself.
x^{2}=\frac{8}{16}
Divide both sides by 16.
x^{2}=\frac{1}{2}
Reduce the fraction \frac{8}{16} to lowest terms by extracting and canceling out 8.
x=\frac{\sqrt{2}}{2} x=-\frac{\sqrt{2}}{2}
Take the square root of both sides of the equation.
16x^{2}-8=0
Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.
x=\frac{0±\sqrt{0^{2}-4\times 16\left(-8\right)}}{2\times 16}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 16 for a, 0 for b, and -8 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 16\left(-8\right)}}{2\times 16}
Square 0.
x=\frac{0±\sqrt{-64\left(-8\right)}}{2\times 16}
Multiply -4 times 16.
x=\frac{0±\sqrt{512}}{2\times 16}
Multiply -64 times -8.
x=\frac{0±16\sqrt{2}}{2\times 16}
Take the square root of 512.
x=\frac{0±16\sqrt{2}}{32}
Multiply 2 times 16.
x=\frac{\sqrt{2}}{2}
Now solve the equation x=\frac{0±16\sqrt{2}}{32} when ± is plus.
x=-\frac{\sqrt{2}}{2}
Now solve the equation x=\frac{0±16\sqrt{2}}{32} when ± is minus.
x=\frac{\sqrt{2}}{2} x=-\frac{\sqrt{2}}{2}
The equation is now solved.