Solve 16x^2-39=(4x-3)^2

$$16 x ^ { 2 } - 39 = ( 4 x - 3 ) ^ { 2 }$$

Solve for x

$$x=2$$

Steps for Solving Linear Equation

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(4x-3\right)^{2}.

$$16x^{2}-39=16x^{2}-24x+9$$

Subtract 16x^{2} from both sides.

$$16x^{2}-39-16x^{2}=-24x+9$$

Combine 16x^{2} and -16x^{2} to get 0.

$$-39=-24x+9$$

Swap sides so that all variable terms are on the left hand side.

$$-24x+9=-39$$

Subtract 9 from both sides.

$$-24x=-39-9$$

Subtract 9 from -39 to get -48.

$$-24x=-48$$

Divide both sides by -24.

$$x=\frac{-48}{-24}$$

Divide -48 by -24 to get 2.

$$x=2$$