Solve 16x^2-16=0

$$16 x ^ { 2 } - 16 = 0$$

Solve for x

$$x=1$$

$$x=-1$$

Steps Using Difference of Squares

Divide both sides by 16.

$$x^{2}-1=0$$

Consider x^{2}-1. Rewrite x^{2}-1 as x^{2}-1^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(x-1\right)\left(x+1\right)=0$$

To find equation solutions, solve x-1=0 and x+1=0.

$$x=1 x=-1$$

Steps by Finding Square Root

Add 16 to both sides. Anything plus zero gives itself.

$$16x^{2}=16$$

Divide both sides by 16.

$$x^{2}=\frac{16}{16}$$

Divide 16 by 16 to get 1.

$$x^{2}=1$$

Take the square root of both sides of the equation.

$$x=1 x=-1$$

Steps Using the Quadratic Formula

Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.

$$16x^{2}-16=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 16 for a, 0 for b, and -16 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 16\left(-16\right)}}{2\times 16}$$

Square 0.

$$x=\frac{0±\sqrt{-4\times 16\left(-16\right)}}{2\times 16}$$

Multiply -4 times 16.

$$x=\frac{0±\sqrt{-64\left(-16\right)}}{2\times 16}$$

Multiply -64 times -16.

$$x=\frac{0±\sqrt{1024}}{2\times 16}$$

Take the square root of 1024.

$$x=\frac{0±32}{2\times 16}$$

Multiply 2 times 16.

$$x=\frac{0±32}{32}$$

Now solve the equation x=\frac{0±32}{32} when ± is plus. Divide 32 by 32.

$$x=1$$

Now solve the equation x=\frac{0±32}{32} when ± is minus. Divide -32 by 32.

$$x=-1$$

The equation is now solved.

$$x=1 x=-1$$