Factor
\frac{16\left(5x-3\right)\left(5x+3\right)}{25}
Evaluate
16x^{2}-\frac{144}{25}
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\frac{16\left(25x^{2}-9\right)}{25}
Factor out \frac{16}{25}.
\left(5x-3\right)\left(5x+3\right)
Consider 25x^{2}-9. Rewrite 25x^{2}-9 as \left(5x\right)^{2}-3^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
\frac{16\left(5x-3\right)\left(5x+3\right)}{25}
Rewrite the complete factored expression.
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