Solve 16x^2+8x^2

$$16 x ^ { 2 } + 8 x ^ { 2 }$$

Differentiate w.r.t. x

$$48x$$

Steps Using Definition of a Derivative

Combine 16x^{2} and 8x^{2} to get 24x^{2}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(24x^{2})$$

The derivative of ax^{n} is nax^{n-1}.

$$2\times 24x^{2-1}$$

Multiply 2 times 24.

$$48x^{2-1}$$

Subtract 1 from 2.

$$48x^{1}$$

For any term t, t^{1}=t.

$$48x$$

Evaluate

$$24x^{2}$$

Solution Steps

Combine 16x^{2} and 8x^{2} to get 24x^{2}.

$$24x^{2}$$