Solve 16x^2+199x+6-y=0

$$16 x ^ { 2 } + 199 x + 6 - y = 0$$

Solve for y

$$y=16x^{2}+199x+6$$

Steps for Solving Linear Equation

Subtract 16x^{2} from both sides. Anything subtracted from zero gives its negation.

$$199x+6-y=-16x^{2}$$

Subtract 199x from both sides.

$$6-y=-16x^{2}-199x$$

Subtract 6 from both sides.

$$-y=-16x^{2}-199x-6$$

Divide both sides by -1.

$$\frac{-y}{-1}=\frac{-16x^{2}-199x-6}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$y=\frac{-16x^{2}-199x-6}{-1}$$

Divide -16x^{2}-199x-6 by -1.

$$y=16x^{2}+199x+6$$

Solve for x (complex solution)

$$x=\frac{\sqrt{64y+39217}-199}{32}$$

$$x=\frac{-\sqrt{64y+39217}-199}{32}$$

Solve for x

$$x=\frac{\sqrt{64y+39217}-199}{32}$$

$$x=\frac{-\sqrt{64y+39217}-199}{32}\text{, }y\geq -\frac{39217}{64}$$