Solve 16x^{-3}y^2*8^-1x^3y^-2

$$16 x ^ { - 3 } y ^ { 2 } \times 8 ^ { - 1 } x ^ { 3 } y ^ { - 2 }$$

Evaluate

$$2$$

Steps Using Commutative Property of Multiplication

Use the rules of exponents to simplify the expression.

$$16^{1}x^{-3}y^{2}\times \frac{1}{8}x^{3}y^{-2}$$

Use the Commutative Property of Multiplication.

$$16^{1}\times \frac{1}{8}x^{-3}x^{3}y^{2}y^{-2}$$

To multiply powers of the same base, add their exponents.

$$16^{1}\times \frac{1}{8}x^{-3+3}y^{2-2}$$

Add the exponents -3 and 3.

$$16^{1}\times \frac{1}{8}x^{0}y^{2-2}$$

For any number a except 0, a^{0}=1.

$$16^{1}\times \frac{1}{8}y^{2-2}$$

Add the exponents 2 and -2.

$$16^{1}\times \frac{1}{8}y^{0}$$

For any number a except 0, a^{0}=1.

$$16^{1}\times \frac{1}{8}$$

Raise 8 to the power -1.

$$16\times \frac{1}{8}$$

Multiply 16 times \frac{1}{8}.

$$2$$

Factor

$$2$$