Solve 16t^3u+20t^3+16t^2u+20t^2

$$16 t ^ { 3 } u + 20 t ^ { 3 } + 16 t ^ { 2 } u + 20 t ^ { 2 }$$

Factor

$$4\left(t+1\right)\left(4u+5\right)t^{2}$$

Solution Steps

Factor out 4.

$$4\left(4t^{3}u+5t^{3}+4t^{2}u+5t^{2}\right)$$

Consider 4t^{3}u+5t^{3}+4t^{2}u+5t^{2}. Factor out t^{2}.

$$t^{2}\left(4tu+5t+4u+5\right)$$

Consider 4tu+5t+4u+5. Do the grouping 4tu+5t+4u+5=\left(4tu+5t\right)+\left(4u+5\right), and factor out t in 4tu+5t.

$$t\left(4u+5\right)+4u+5$$

Factor out common term 4u+5 by using distributive property.

$$\left(4u+5\right)\left(t+1\right)$$

Rewrite the complete factored expression.

$$4t^{2}\left(4u+5\right)\left(t+1\right)$$

Evaluate

$$4\left(t+1\right)\left(4u+5\right)t^{2}$$